The length of a rectangle is 1 units more than the width. The area of the redangle is 56 units. What is the width, in units, of the rectangle?

27.5 is the width

Step-by-step explanation:

First set up an equation.

(w+1)+w=56

This simplifies to...

2w+1=56

Now you need to isolate the w. Subtract 1 on both sides.

2w=55

Now divide 2 on both sides.

55/2 = 27.5

w=27.5

Hopefully you understand! Please give this "brainliest"! Thank you and have a great day! :)

The width is 7 units.

Step-by-step explanation:

What we know:

- Area of the rectangle is 56

- The length of a rectangle is 1 unit more than the width

I will be using the variable w to represent the width.

Let's write it out:

Length = w + 1

Width = w

We know that the area is length x width

So the equation is (w + 1) x w = 56

Let's simplify this equation!

w^2 + w = 56

Now we need to find the solutions of this equation and see which one works.

Rewrite the eqaution:

w^2 + w - 56 = 0

Factor, find two factors of -56 whose sum equals the coefficient of the middle term (w):

-7, 8

Rewrite:

w^2 - 7w + 8w - 56 = 0

This part is a little tricky for me to explain, I apologize in advance for any confusion, but you want to do a little something like this:

(w+8) x (w-7) = 0

Now we solve both terms by = 0 seperately:

w + 8 = 0

= -8

w - 7 = 0

w = 7

Solutions:

w = 7, -8

Now that we have our solutions, we can choose which one best fits our scenario. In this case, 7 will fit the best.

To check this, we just plug it all in!

Length: 7 + 1 = 8

Width: 7

Area is length x width. So now we multiply:

8 x 7 = 56.

The width of this rectangle is 7 units.

y=mx+

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.