HELP
if a+1 is divisible by 3 prove that 4+7a is divisible by 3 too

Step-by-step explanation:

Assume there exists integer k such that 3k=a+1.

4+7a

=7a+4

=7(a+1)-3

=7(3k)-3

=3(7k-1)

This implies that if there exists integer k such that 3k=a+1 then there is integer 7k-1 such that 3(7k-1)=4+7a

1. minimum

2. 6400

3. eight

hope this !

answer: 8

step-by-step explanation: if you add the possibilities 5 different flavor and 3 different sizes 5+3=8