If the measure of angle AXC =8x-7 and the measure of angle AXB=3x+10 what is the measure of angle AXC?

<AXC = 101 degrees.

Step-by-step explanation:

The question says that XB is a bisector which means that <AXB = 1/2 of AXC

You can't do the question if that assumption isn't true.

<AXC  = 8x - 7

<AXB = 3x + 10

3x + 10 = 1/2 ( 8x - 7)     Multiply both sides by 2

2(3x + 10) = 8x - 7         Remove the brackets

6x + 20 = 8x - 7             Add 7 to both sides

6x + 20 + 7 = 8x            Combine

6x + 27 = 8x                  Subtract 6x from both sides

27 = 8x - 6x                  Combine

27 = 2x                          Switch

2x = 27                          Divide by 2

x = 27/2

x = 13.5

AXC = 8x - 7

AXC = 8*13.5 - 7

AXC = 108 -7

AXC = 101

a² + b²= c²

24² + 7² = c²

c= 25

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap