The word problem below has too little information. Read carefully, then choose the fact or facts needed to solve the problem.
A group of friends wants to ride the ferris wheel at the same time.
How many empty cars will they need in order to ride together?
A. There are 15 people in the group.
B. From the top, you can see the entire city.
O c. One car on the ferris wheel seats 3 people.
D. A ride on the ferris wheel lasts 5 minutes.
SUBMIT

yes

step-by-step explanation:

they have to be opposite and reciprocal of eachother.

no

explanation:

you can be freinds, and people but not follow people.

you need to rotate this triangle about the origin 270 degrees clockwise to create the full square.

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.