In the pair competition of Olympic figure skating, a 60-kg male skater pushes a 45-kg female skater. If the push caused the female to accelerate at 2.0 m/s, what is the acceleration of the male skater?

Step-by-step explanation:

Male=60kg

female=45kg

accelerate= 2.0 m/s

solution,

Here,

a= v-u

2.0= 60-45

2.0 = 15

= 15-2.0

Accelerate = 13 m/s is a male skater .

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

answer: the four apples you took away.

step-by-step explanation: