40 points PLEASE HELP!! seth is using the figure shown below to prove the pythagorean theorem using triangle similarity: in the given triangle DEF angle D is 90 and segment DG is perpendicular to segment EF

I found the corresponding image.

The step towards proving the similarity of triangles DEF and GED is:

ANGLE E IS CONGRUENT TO ITSELF.

ΔDEF is a right triangle. Its hypotenuse is EF, its long leg is DF, its short leg is DE.

ΔGED is also a right triangle. Its hypotenuse is DE, its long leg is DG, its short leg is GE.

Only Angle E is in both triangles and its measure remains the same.

Step-by-step explanation:

I found the corresponding image.

The step towards proving the similarity of triangles DEF and GED is:

ANGLE E IS CONGRUENT TO ITSELF.

ΔDEF is a right triangle. Its hypotenuse is EF, its long leg is DF, its short leg is DE.

ΔGED is also a right triangle. Its hypotenuse is DE, its long leg is DG, its short leg is GE.

Only Angle E is in both triangles and its measure remains the same.

Step-by-step explanation:

8

step-by-step explanation:

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: