Given a*b = 3a²b, determine: a) (2*1) b) (2*1) *3 2. Given n#m = √3mn, determine a) 2#6 b) (4#3) #2 ​

1a)12 b)1296 2a)6 b)6

Step-by-step explanation:

1a)a*b=3a^2b

(2*1)=3*2^2*1

=3*4*1

=12.

b)(2*1)*3=12*3

=3*12^2*3

=3*144*3

=1296.

2a)n#m=√3mn

2#6=√3*2*6

=√36

=6.

b)(4#3)#2

(4#3)=√3*4*3

=√36

=6

6#2= √3*6*2

= √36

=6

its 4 because 2 times 2 is 4, if you double the number two you get four