A ball is thrown into the air with a velocity of 35 ft/s. Its height, in feet, after t seconds is given by s(t) = 35t − 16t2.
Find the velocity (in ft/s) of the ball at time
t = 1 second.

Answer explained below

Step-by-step explanation:

the equation of motion when an object is accelerated is given by:

where

x - is the current position(or displacement) of the body

x0 is the initial position

v0 is the initial velocity

a is acceleration

t is time

We rewrite the equation

which is similar to the equation above, which means we can rewrite the following equation like this:

so, in our case:

x0 = 0

v0 = 35 m/s

Now, since this is an accelerated motion it means that the velocity of the body changes as well due to acceleration with the equation:

acceleration is negative, therefore:

t = 1 results:

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.