Find the slope of the line that passes through the two points below.
(3,4) and (3,-1)

Slope = (-5,0)

Step-by-step explanation:

When given two points and asked to find the slope, you can find the answer using slope formula which is:

slope = (y2 - y1) / (x2-x1)

You have been given the points (3,4) and (3,-1). You can select which ones to be x1 and y1 and which ones to be x2 and y2. It doesn't matter which, so let's just do (3,4) are x1 and y1 and (3,-1) are x2 and y2. Now we can plug it into the formula.

Slope = (-1 - 4) / (3-3)

= -5 / 0

= -5,0

So the answer is (-5,0).

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.