Write the equation of the line perpendicular to y=3x-1 that passes through the point (3,-4) explanation or step by step pls

thanku

Step-by-step explanation:

Hi there!

We want to write an equation of the line that is perpendicular to y=3x-1 and passes through (3, -4)

Perpendicular lines have slopes that multiply to get the value of negative one.

Let's first figure out the slope of y=3x-1

The line is written in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

3 is in the place of where m is, so 3 is the slope of y=3x-1

Now let's find the slope of the line perpendicular to it.

We can use a formula like this:

If 3 is , then:

Divide both sides by 3

So the slope of the perpendicular line is -1/3

We can write this equation in slope-intercept form. So far, we know that the equation of the line is:

y=

So let's find b

Remember that we are given that the line passes through the point (3, -4). That means that point is a solution to the equation that we're trying to find. Therefore, the values of that point should create a true statement when plugged into the equation.

So we can substitute 3 as x and -4 as y to help solve for b.

-4=

Multiply

-4= + b

Simplify

-4 = -1 + b

Add 1 to both sides to isolate b

-3 = b

Substitute -3 as b in the equation

Hope this helps!

step-by-step explanation:

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.