SOLVE FASTTT The base of a triangle is 9 cm correct to the nearest om
The area of this triangle is 40 cm correct to the nearest 5
Calculate the upper bound for the perpendicular height of this
triangle

Step-by-step explanation:

Area of triangle is 40 cm² correct to nearest 5cm² .

∴ Area of triangle = ( 40 ± 5) cm²

∴ upper bound for area of triangle is = (40 + 5) cm² = 45cm²

Base of triangle = 9cm

∵ area of triangle = 1/2 base × height

height = 2 × area of triangle/base

∴ upper bound for height of triangle = 2 × upper bound area/base

= 2 × 45/9 = 10cm

Hence answer is 10cm

whats the question?

step-by-step explanation:

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c