Could you please help me with that question, please step by step Construct one table that includes relative frequencies based on the frequency distributions shown​ below, then compare the amounts of tar in nonfiltered and filtered cigarettes. Do the cigarette filters appear to be​ effective? (Hint: The filters reduce the amount of tar ingested by the​ smoker.)

7-11 Relative Frequency (nonfiltered) Relative Frequency (filtered)
12-16
17-21
22-26
27-31
32-36
37-41

Relative Frequency (filtered)

Transcribed image text: Construct one table that includes relative frequencies based on the frequency distributions shown below, then compare the amounts of tar in nonfitered and fitered cigarettes. Do the cigarette filters appear to be effective? (Hint: The filters reduce the amount of tar ingested by the smoker) m Click the icon to view the frequency distributions. Frequency Distributions Complete the relative frequency table below. Relative Relative Frequency Frequency Tar (mg) (Nonfiltered) (Filtered) 2-6 Tar (mg) in Tar (mg) in 7-11 Nonfiltered Filtered Cigarettes Frequency Cigarettes Frequency 12-16 12-16 2-6 17-21 17-21 7-11 22-26 12-16 22-26 27-31 17-21 27-31 32-36 32-36 (Simplify your answers.) Print Done Do cigarette filters appear to be effective? O A. No, because the relative frequency of the higher tar classes is greater for filtered cigarettes. O B. Yes, because the relative frequency of the higher tar classes is greater for nonfiltered cigarettes. OC. No, because the relative frequencies for each are not substantially different O D. This cannot be determined.

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5