Triangle ABC has its vertices at the following coordinates: A(-5, 2) B(-3, 1) C(-1, 5)

Give the coordinates of the image triangle A'B'C' after a 90° counterclockwise rotation about the origin.

Please explain how you got it

A(-5, 2) B(-3, 1) C(-1, 5) ==> A(-2, -5) B(-1, -3) C(-5, -1)

Step-by-step explanation:

90° counterclockwise rotation about the origin: (x,y) > (-y,x)

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

0/5 is 0, 2/0 is undefined, and 0/0 is indeterminate.

step-by-step explanation:

hope my answer has you!