A container has 300 liters of water, and a second container has 700 liters of water. The first container begins filling up at a rate of 5 liters per minute at the same time the second starts draining at a rate of 6 liters per minute. Which equation can be used to find the number of minutes, x, that elapse before the two containers have the same amount of water?

After t minutes, the first container holds

300 + 5t

liters of water, while the second container holds

700 - 6t

liters of water. The two containers hold the same amount of water when

300 + 5t = 700 - 6t

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

c = 0.429t

step-by-step explanation:

the constant rate at which carlos harvests cassava is 35 minutes per 15 cassavas 15/35 = 0.429 cassava per minute

therefore, an equation that models the number of cassava (c) that harvest carlos in a time (t) is the following:

where t is the time in minutes.

this means that when 35 minutes have elapsed 15 cassava have been harvested, at 70 minutes 30 cassava have been harvested and so on.