When Mr. Rodgers was in the Air Force, he was responsible for maximizing how much his aircraft flew, which also meant taking time to fix them. For every hour an aircraft flew, it would require (on average)
three hours of maintenance. What's the greatest number of hours each aircraft could fly in a day (i. e.
24hrs) while still being fully maintained and ready to fly the next day?

Show me how you solved the question please

the answer is 15% decrease

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15