QUICK, NEED ANSWER TO THIS MATH QUESTION! PLEASE HELP!!!

n = 11

Step-by-step explanation:

let first odd number be n(as stated in question)

to have the next consecutive odd number, add 2 to the n:

1st odd number = n

2nd odd number = n + 2

3rd odd number = n + 4

following the qn, sum of n, twice of n + 2 and thrice of n + 4 is 82

thus n + 2(n+2) + 3(n+4) = 82

n + 2n + 4 + 3n + 12 = 82

6n = 66

therefore n = 11

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.