Can someone PLEASE HELP ME ON NUMBER 10 ONLY PLEASE ITS MY LAST QUESTION ILL GIVE YOU BEAINLIEST AND PTS

Step-by-step explanation:

XB bisects ∠AXC.

⇒ ∠AXB = ∠BXC = 6x + 40

  ∠AXB + ∠BXC = ∠AXC

6x + 40 + 6x + 40 = 7x + 100

6x + 6x + 40 + 40 = 7x + 100

Add like terms

12x + 80 = 7x  +100

Subtract 80 from both sides

12x = 7x + 100 -80

12x = 7x + 20

Subtract 7x form both sides

12x - 7x = 20

5x = 20

Divide both sides by 5

x = 20/5

x = 4

∠AXC = 7x + 100

           = 7*4 + 100

          = 28 + 100

 ∠AXC = 128

(-1,-0.5)

step-by-step explanation:

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step-by-step explanation: