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Mathematics, 23.09.2021 23:20 CameronVand21

Can someone solve this? Given that
show that
Hence, find the solution, in radians, of the equation
for


\sec(x)  - 5 tan(x)  = 3cos(x)
3 {sin(x) }^{2}  - 5 sin(x)  - 2 = 0
\sec(x)  - 5 \tan(x)  =3  \cos(x)
- \pi \leqslant x \geqslant \pi

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Answers: 2

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