Mia and John are selling boxes of apples. They have small boxes and large boxes. Mia sells 6 small boxes and 2 large boxes for a total of $28. John sells 4 small boxes and 5 large boxes for a total of $37. How much does each small box and each large box cost?

so

6s+2l = 28

4s+5l=  37

eliminate 6s+2l=28 by dividing all numbers by 6

u get s= -1/3 l + 14/3

49-1/3l=14/3) + 5l =37

L=5

s= -1/3(5) + 14/3

s=3

l=5

Smalls boxes: $3

Large boxes: $5

Step-by-step explanation:

Small boxes: x

Large boxes: y

6x + 2y = 28

4x + 5y = 37

I will use elimination to solve it.

2(6x + 2y = 28) = 12x + 4y = 56

-3 (4x + 5y = 37) = -12x + 15y = -111

(4y = 56) + (-15y = -111)

4y -15y = -11y and 56 - 111 = -55

-11y = -55

y = 5

6x + 2(5) =28

6x = 28-10

x = 18/6

x = 3

step-by-step explanation:

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0