Give 100 points How many 58-digit numbers are there where the sum of the digits is 31, and each digit has a adjacent number different parity?

Given two integers ‘n’ and ‘sum’, find count of all n digit numbers with sum of digits as ‘sum’. Leading 0’s are not counted as digits.

1 <= n <= 100 and

1 <= sum <= 500

Example:

Input: n = 2, sum = 2

Output: 2

Explanation: Numbers are 11 and 20

Input: n = 2, sum = 5

Output: 5

Explanation: Numbers are 14, 23, 32, 41 and 50

Input: n = 3, sum = 6

Output: 21

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right