Please help will mark BRAINLIEST (Can you just show what it would look like on the graph I can’t fit all the answer choices )

See Below

Step-by-step explanation:

The graph should look something like this.

Make sure that the points at (-2,2) and (2,-2) have open circles as shown in the image below. Also make sure that the points (-2,4) and (2,-3) have closed circles also shown in the image below.

Also make sure that the line extends infinitely from (-2,4) to the left and infinitely from (2,-3) to the right.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

x + 4/7

step-by-step explanation:

use cymath