SOMEONE HELP ME PLEASE

Angle 1 = 105°

Angle 2 = 75°

Angle 3 = 75°

Angle 4 =105°

Angle 5 =75°

Angle 6 =75°

Angle 7 = 75°

Angle 8 =105°

Step-by-step explanation:

Hey mate answer is simple just go through my explanation:)

Angle 2 = ?

Here we see that both angle 1 and angle 2 forms linear pair.

Which means they are supplementary.

So therefore the Angle 2 will be

So angle 2 will be 75°

Now,

Angle 3 = ?

Angle 3 will also be 75° because it is vertically opposite to angle 2 ( which is also 75°) and we know that vertically opposite angles are always equal.

So angle 3 will be 75°

Now,

Angle 4 = ?

Angle 4 will be 105 ° because it is vertically opposite to angle 1 ( which is also 105° ) and we know that vertically opposite angles are always equal.

So angle 4 = 105°

Now,

Angle 5 = ?

Angle 5 will be 105° because it is corresponding to angle 1 and we know that corresponding angles are always equal.

So angle 5 = 105°

Now,

Angle 6 = ?

Angle 6 will be 75° because it is corresponding to angle 2 and we know that corresponding angles are always equal.

So angle 6 = 75°

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Extra Information

Angle 7 is vertically opposite to angle 6 so Angle 7 will be 75°

And Angle 8 is vertically opposite to angle 5 so angle 5 will be 105°

Hope it helps you!!

#IndianMurgaツ

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1