Brian will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $49 and costs an additional $0.13 per mile driven. The second plan has an initial fee of $40 and costs an additional $0.17 per mile driven.

You did not ask a specific answer and only gave us a scenario. Therefore I could only set up equations for both plans. I hope they help!

Step-by-step explanation:

First plan: y = 0.13x + 49

Second plan: y = 0.17x + 40

0.13 and 0.17 = The amount of money Brian has to pay per mile in each plan

x = The number of miles that were driven in each plan

49 and 40 = The base cost of each plan

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.