Find the equation of the line. a line that is perpendicular to the graph of 3x+2y=6 and contains the point (6, -3)
100 POINTS
BRAINLIEST
ASAP

y = 2/3x - 7

Explanation:

First we must turn 3x + 2y = 6 to slope intercept form. In order to do this first subtract 3x on both sides of the equal sign, so we can get 2y by its self. Now we're left with 2y = -3x + 6 .

Next divide 2 from both sides to get y by its self. Now you got y = -3/2x + 3 (since 6 can be divided by 2 it's a 3 now) Look above to see y= -3/2x +3 graphed. ⤴⤴⤴

To find out the other equation we first need to know what its y-intercept is, and luckily for us we've already been given -3.

Look above to see (6,-3) graphed. ⤴⤴⤴

Look above to see both y = -3/2x + 3 and

y = 2/3x -7 graphed. ⤴⤴⤴

This is a bit lengthy, but I hope you get it :)

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!