2) Select the algebraic definition for the piecewise function graph. F(x){_ 0< = x < 2
{_ 2 < = x < 4

A. 2x-8
B. 2
C. -2x+8
D. 4
E. 2x-4

The answer is C - 2x + 8.

Step-by-step explanation:

In the first domain:

does not exist.

in the second domain:

The function is:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

explanation:

step-by-step explanation: