Please help me with problems 1-3

1. 1st term 37

f(n) = f(n -1) - 10

f(2) = f(2 - 1) - 10

f(2) = f(1) - 10

f(2) = 37 - 10 = 27

f(3) = f(3 - 1) - 10

f(3) = f(2) - 10

f(3) = 27 - 10

f(3) = 17

f(4) = f(4 - 1) - 10

f(4) = f(3) - 10

f(4) = 7

f(5) = f(5 - 1) - 10

f(5) = 7 - 10

f(5) = -3

the first 5 terms are, 37,27,17,7and -3.

2. first term is 8

f(n) = 4 + f(n - 1)

f(2) = 4 + f(2 - 1)

f(2) = 4 + 8 = 12

f(3) = 4 + f(3 - 1)

f(3) = 4 + 12 = 16

f(4) = 4 + f(4 - 1)

f(4) = 4 + 16 = 20

f(5) = 4 + f(5 - 1)

f(5) = 4 + 20 = 24

the first 5 terms are, 8,12,16,20and 24.

3. first term is 18.

f(n) = f(n - 1) + 100

f(2) = f(2 - 1) + 100

f(2) = 18 + 100 = 118

f(3) = f(3 - 1) + 100

f(3) = 118 + 100 = 218

f(4) = f(4 - 1) + 100

f(4) = 218 + 100

f(4) = 318

f(5) = f(5 - 1) + 100

f(5) = 318 + 100 = 418

the first five terms are, 18,118,218,318and 418.

step-by-step explanation:

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!