The equation for line j can be written as y = x + 7. Parallel to line j is line k, which passes through the point (-3, -1). What is the equation of line k?

Step-by-step explanation:

parallel lines have the same gradient..

y=x+7 has a gradient of 1.

If line J which is parallel to k has a gradient of 1 then they are the same.

gradient (m) =∆y

∆x

=y- -1 = 1

x - - 3

= y + 1

x+3

y+1=x+3

y=x +3 +1

y = x + 4(equation for k)

could you provide figure.

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step-by-step explanation: