HELP dose anyone know Lin and Andre method for area?

Andrea Area = 4 x 10.7 + 20 = 62.8cm

Where Lin would be slightly smaller due to inequality Lin Area = 60cm

Therefore Andréa's area = 62.8cm is more precise to 2 and 3 significant figures.

Step-by-step explanation:

Lin and Andre used different methods to find the area of a regular hexagon with 5 cm sides. Lin decomposed the hexagon into six identical triangles. Andre decomposed the hexagon into a rectangle and two triangles. Find the area of the hexagon using each person’s method. Show your reasoning.

Lins Hexagon = 6 triangles

Formula see picture why we say 4 x isosceles for Andre

You will notice that a rectangle is formed using 2 isosceles triangles and 2 equilateral triangles. So as these reflect we show a formula of 4 isosceles.

Lin = 6 x TA

Andre =  4 x isosceles Area  + 2 x Equilateral

Therefore if a side measures 5cm

Lin = 1/2 x 5 x 2.5 = 10cm

6 triangles = 10 x 6 = 60cm  

If Andres hexagon is also 5cm sides = 10cm area

Then 2x 10 = 20

and isosceles = 5cm edges

The rest is found Pythagoras

5^2 - 2.5^2 = 4.33^2

4.33 x 2 = 8.66 as we halved the triangle and the sq rt is already squared as 4.33 to find c.

however area = 1/2 x 4.3 x 2.5 = 5.35 each half

= 10.7  per isosceles

Area = 4 x 10.7 + 20 = 62.8cm

therefore Andréa's area = 62.8cm is more precise to 2.8cm

36 is the final answer! : )

because they could drop even lower..