Let f(x) =2x+4 although lim x->5 f(x) =14 only one of the sentences bellow is true

for every real number x, if 0 < |x-5|<2,then |f(x)-14|<1
for every real number x, if 0 < |x-5| <2 then |f(x)-14|<2
for evert real number x, if 0 < |x-5| <1, then |f(x)-14|<2

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

answ5

step-by-step explanation:

u have to pay atttion to me

i believe the answer is 323 ft

step-by-step explanation:

answer. d.289 hope that