Find 2 integers whose sum is 16 and the product is 80

No solution in real numbers

Step-by-step explanation:

a+b=16

a*b=80

Unfortunately it does not have solution

I think the question is mistyping or wrong

Step-by-step explanation:

A+B=16

A*B = -80

Convert to

A=16-B

Substitute

(16-B)*B=-80

16B-B^2+80=0

Change the sign to make it easier (multiply by negative number)

B^2 -16B-80

=(B - 4)(B + 20)

B1=-4 and B2=20

Then its match if the product is -80.

Or second option is, assuming that the sum is 18, not 16

The A would be 8 and the B would be 10

its 69.420

step-by-step explanation:

costs the what? what is the cost of the pants?

step-by-step explanation:

if it is $10, then the price is 14.

take 40% of the cost, and then add the cost.

40% of 10 = 4

4+10 = 14.