If f(x)=(x^2 - 3)^4, then f'(1) = ?

f(1) = 16

Step-by-step explanation:

Substitute x = 1 into f(x) , that is

f(1) =

     =

     =

    = 16

16

f(x) = (x² - 3)⁴

f(1) = (1² - 3)⁴

f(1) = (-2)⁴

f(1) = (-2 × (-2) × (-2) × (-2))

f(1) = (-4 × (-2) × (-2))

f(1) = (-8 × (-2))

f(1) = 16

If f(x) = (x² - 3)⁴ then f(1) is 16.

answer: rolling a number cube and flipping a coin.

step-by-step explanation:

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96