What is the equation of the line that passes through the point (6,−7) and has a slope of -3/2

y = -3/2x + 2

Step-by-step explanation:

slope-line equation : y = mx + b

slope is -3/2

Let's find the y-intercept using (6, -7)

y = mx + b

-7 = -3/2(6) + b

-7 = -18/2 + b

-7 = -9 + b

+9   +9

2 = b

So, y = -3/2x + 2 is your equation.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: