Simplify: j + 5 + 5c

Which is equivalent to 10/12? options: 10/18 5/6 3/12 9/11

The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. if a sample of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. what is the margin of error of the sample mean? a. 0.086% b. 0.533% c. 1.11% d. 2.22%

Math it's appreciated. (picture provided)