Find the period of cos (3x+5)+7.

Step-by-step explanation:

Given function is: f(x) = cos(3x + 5) +7 Let the function be periodic with period A, then according to the

property of periodicity,

» f(x+A) = f(x)

→ cos(3(x + A) + 5) + 7 = cos(3x+5)+7

→ cos (3(x+A)+5) = cos(3x + 5)

→ cos(3x + 5+ 3A) = cos(3x + 5)

: We know that, cos(0° (threata) +2π) = cos(0° (threata) )

→ 3A = 2π

» A = 2π / 3

Thus, the period of given function cos(3x+5) = 2π/3

Given function is: f(x) = cos(3x + 5) +7 Let

the function be periodic with period A,

then according to the

property of periodicity,

> f(x+A) = f(x)

→ Cos(3(x + A) + 5) + 7 = cos(3x+5)+7

Step-by-step explanation:

→ COS (3(x+A)+5) = cos(3x + 5)

COS(3x + 5+ 3A) = cos(3x + 5)

: We know that, cos(Oº (threata) +21) =

cos(Oº (threata))

→ 3A = 21

» A = 2/3

Thus, the period of given function

cos(3x+5) = 21/3

10x

step-by-step explanation:

the greatest common factor 30 and 20 is 10

5 is a common factor of 30 and 20 but 10 is also a factor and 10 is greater than 5 so 5 will definitely not be apart of our answer

now the most amount of x's you factor our is just 1 factor of 1

so 10x the gcf of the terms in the polynomial

answer: r there any options?

step-by-step explanation: