Omer Ahmed Quadratic Word Problems (Gravity)

Oct 08, 1:58:10 PM

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A rocket is launched from a tower. The height of the rocket, yin feet, is related to the

time after launch, x in seconds, by the given equation. Using this equation, find the

time that the rocket will hit the ground, to the nearest 100th of second

y=-162° +1242 + 127

Sattumit. As

answer: ask

step-by-step explanation:

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!

the correct answer would be:

220 centimeters

to get this you can use the pythagorean theorem

hope this

step-by-step explanation: