(a) Write the point–slope form of a function that has a slope of 3- 5 and passes through the point (6,1). (b) Algebraically manipulate your answer in part a to produce the slope– intercept form of the function that has a slope of 3 - 5 and passes through the point (6,1).

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2