Point Fis on line segment EG. EG = 100, EF = 4x - 20, and FG = 2x + 30. Write an equation that you would use to solve for x, then state the value of x, and the length of line segments EF and FG.

Step-by-step explanation:

Line segment = EG

point on a line segment = F

EG = 100

EF = 4x - 20

FG = 2x + 30

a/q, EF + FG = EG

the equation is

4x - 20 + 2x + 30 = 100

now solution for x is

→ 4x - 20 + 2x + 30 = 100

→ 6x + 10 = 100

→ 6x = 100 - 10 = 90

→ x = 90/6 = 15

therefore, value of x is 15.

and according to given information

EF = 4x - 20 = 4(15) - 20 = 60 - 20 = 40

FG = 2x + 30 = 2(15) + 30 = 30 + 30 = 60

hope this answer helps you dear..take care and may u have a great day ahead!

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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