PLEASE HELP!! Find the equation of the line that is perpendicular to the line
6x – 4y = 3 and passes through the point (6,-1).

(a) Find the slope of the given line 6x – 4y = 3.

(b) What is the slope of a line that is perpendicular to the above line?

(c) Now, find the equation of the perpendicular line that passes through (6,-1).

a). y = 3/2x - 3/4    b).-2/3       c).y = -2/3x + 3

Step-by-step explanation:

a). 6x – 4y = 3

-4y = -6x + 3

y = 3/2x - 3/4

 - The slope is 3/2.

b). The slope of a perpendicular line would be the opposite: -2/3

c). y = -2/3x + b

-1 = -2/3(6) + b

-1 = -4 + b

3 = b

y = -2/3x + 3

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2