A group consisting of 6 people is to be selected from eight parents and four teachers. Find the probability of selecting three parents and three teachers.

9/32 or 0.28125

Step-by-step explanation:

8 parents and 4 teachers

There are 12 possible outcomes.

probability = # of favorable outcomes / # of possible outcomes

Let's do the teachers first.

There are 4 teachers, and we are finding the probability for 3 of them being picked.

Therefore,

P = 3/4

Now let's do the parents.

There are 8 parents, and we want 3.

Therefore,

P = 3/8

Now, we do  

Therefore, the chance of 3 teachers and 3 parents being picked out of 4 teachers and 8 parents is 9/32, or in decimal form 0.28125.

Hope this helped!

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

3,750 deer

step-by-step explanation:

1,500 is 15 times larger than 100

lets make 250 15 times larger.

3750 deer