Factorize 18x-2x^3+9-x^2

(3 - x)(3 + x)(2x + 1)

Step-by-step explanation:

18x - 2x³ + 9 - x² ( factor the first/second and third/fourth terms )

= 2x(9 - x²) + 1 (9 - x²) ← factor out (9 - x²) from each term

= (9 - x²(2x + 1) ← 9 - x² is a difference of squares a² - b² = (a - b)(a + b) )

= (3² - x²)(2x + 1)

= (3 - x)(3 + x)(2x + 1)

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.