Harvey is 3 times as old as Jane. The sum of their ages is 52 years. Find the age of each. A. Jane is 13 and Harvey is 39
B. Jane is 12 and Harvey is 48
C. Jane is 13 and Harvey is 48

A. Jane is 13 and Harvey is 39

Step-by-step explanation:

Let's say Harvey's age is H and Jane's age is J

Given:

H = 3J

H + J = 52

Use substitution to find Jane age:

H + J = 52

(3J) + J = 52

4J = 52

J = 13

Plug J-value in any equation to find H-value:

H + J = 52

H + 13 = 52

H = 39

Therefore, Jane is 13 and Harvey is 39. Answer A would be the correct answer.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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