The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. Which of the following equations could be used to find the smaller integer, n? (1) (n+1)+(n+3) = 20 - 4n
(2) n+(n+2) = 4n-20
(3)(n+3)+n=20-4n
(4) n+(n+2) = 4(n-20)