Please help

4a+5b-6c=2

-3a-2b+7c=-15

-a+4b+2c=-13

4a + 5b - 6c = 2

in this equation we don't have any same families cuz three letters are different to one another. so we can do is

Let's solve for a.

4a+5b−6c=2

Step 1: Add -5b to both sides.

4a+5b−6c+−5b=2+−5b

4a−6c=−5b+2

Step 2: Add 6c to both sides.

4a−6c+6c=−5b+2+6c

4a=−5b+6c+2

Step 3: Divide both sides by 4.

4a/a = -5b +6c +2 / 4

a = -5/4 b + 3/2 c + 1/2  

−3a−2b+7c=−15

Step 1: Add 2b to both sides.

−3a−2b+7c+2b=−15+2b

−3a+7c=2b−15

Step 2: Add -7c to both sides.

−3a+7c+−7c=2b−15+−7c

−3a=2b−7c−15

Step 3: Divide both sides by -3.

a = -2/3 b + 7/3 c + 5

-a+4b+2c = -3

−a+4b+2c=−3

Step 1: Add -4b to both sides.

−a+4b+2c+−4b=−3+−4b

−a+2c=−4b−3

Step 2: Add -2c to both sides.

−a+2c+−2c=−4b−3+−2c

−a=−4b−2c−3

Step 3: Divide both sides by -1.

a=4b+2c+3

Step-by-step explanation:

1. perpendicular

2. parallel

3. perpendicular