f is a polynomial of degree 3. f has a root of multiplicity 2 at u=4, f(−4)=0, and f(0)=−28.8. Find an algebraic equation for f. Round all answers to 3 decimal place as/if needed

Step-by-step explanation:

We are given that function f is a polynomial of degree 3. It has a root of multiplicity 2 at u = 4, f(-4) = 0, and f(0) = -28.8. We want to determine an algebraic equation for f.

First, since it has a root of multiplicity 2 at u = 4, one factor is:

Furthermore, since f(-4) = 0, f has another root at u = -4. Since the degree of f is 3, the multiplicity of this root must be 1. Hence, the other factor is:

Hence, our function is:

Since f(0) = -28.8, f = -28.8 when u = 0. Find a:

In conclusion, our function will be:

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: