Find the equation of the tangent line to the curve
y=5 ln(x2ex3)
at the point (1,5). (...
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Mathematics, 17.10.2021 05:30 kseniyayakimov
Find the equation of the tangent line to the curve
y=5 ln(x2ex3)
at the point (1,5). (Hint: simplify before differentiating.) Your answer must be an equation of the form y=mx+b.
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Answers: 3
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