I was given this question as part of my homework and I don't get how they came to the answer, please give step by step so I can understand how it is solved. 6x(x²-36)=0

The answers are 0, -6, 6

Step-by-step explanation:

So we have the equation:

6x(x^2 - 36) = 0

Multiply 36 x 6(the outside number)

6x(x^2 - 216)

Add x and x^2

6x^3 - 216 = 0

Now lets get rid of the exponents.

Split -216 into two equations. 6 x -6 = -216.

So the equations we have are:

(x + 6) and (x - 6)

Put this together with the 6x we have:

6x(x + 6)(x - 6) = 0

Now separate them into three problems:

6x = 0, x + 6 = 0, x - 6 = 0

Find x for all of them.

The answers are 0,-6, and 6.

Btw this is what I think you meant by solving it. If I got the wrong idea, let me know and I’ll fix it.

asdsad

step-by-step explanation: