What is the function g(x) created from f(x) = x2 by moving the graph left 2 units, vertically stretching it by a factor of 3, and shifting the graph up 5 units? A) g(x) = 2(x + 3)2 + 5 B) g(x) = 3(x − 2)2 + 5 C) g(x) = 3(x + 2)2 + 5 D) g(x) = 5(x + 3)2 + 2

Point r divides in the ratio 1 : 3. if the x-coordinate of r is -1 and the x-coordinate of p is -3, what is the x-coordinate of q? a. b. 3 c. 5 d. 6 e. -9

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.

What is the circumference of a circle with an area of 50.24 cm²?