PLEASE HELP A ball is thrown into the air from a height of 6 ft. The height, h, of the ball after t
seconds, is given by the equation h= -4.9+2 + 40t + 6. What is the maximum height
the ball reaches?
between 70 ft and 75 ft
between 75 ft and 80 ft
over 85 ft
between 80 ft and 85 ft

Over 85 ft

Step-by-step explanation:

The maximum height of the ball is going to be located at the vertex of the parabola. First you need to find the x (or t in this case) coordinate for the axis of symmetry. Using the equation for the axis of symmetry of a parabola:

After finding the t-coordinate for the vertex, then plug this value into the original equation to find the corresponding h-coordinate:

Assuming the equation is ,

So the vertex can be represented as (4.016, 87.6327)

The maximum height is over 85 ft.

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.