Which is the best approximation for the solution of the system of equations? y = A system of equations. y equals negative StartFraction 2 over 5 EndFraction x plus 1. y equals 3 x minus 2.x + 1
y = 3x – 2

A coordinate grid with 2 lines. The first line passes through (0, 1) and (5, negative 2). The second line passes through (0, negative 2) and (1, 1). the lines appear the intersect at a point that is almost to 1 and almost to 1.
(0.45, 0.88)
(0.88, 0.65)
(0.88, 1.1)
(1.3, 0.88)

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.