Learning Task 3 . Find the equation of the line. Do it in your notebook. (a) In slope intercept form y = mx + b
(b) in standard form ax + by = c
1. The slope is 5 passing through (-1, 4).
2. The line passes through point (3, -4) and (-2, 2)
3. The slope is 3/4 and the y-intercept is (0,4)
4. The x intercept -3 and the y-intercept is 6
5. Passing through the points (-1, -2) and (5, 3)

Step-by-step explanation:

1. The slope is 5 passing through (-1, 4).

 y=mx+b

y=5x+b [slope is 5]

4 = 5(-1) + b  [Find b by solving for b with the given point]

b = 9

y=5x+9

2. The line passes through point (3, -4) and (-2, 2)  

Calculate slope from the "rise" over the "run."

Rise = (-4 - 2) = -6

Run = (3-(-2)) =  5

Slope - Rise/Run = -6/5 or -1.2

y = -1.2x + b

Use either given point to find b.

y = -1.2x + b  for (3,-4)

-4 = -1.2(3) + b

-4 = -3.6 + b

b = -0.4

y = -1.2x - 0.4

3. The slope is 3/4 and the y-intercept is (0,4)

y = mx + b

y = (3/4)x + b

The y-intercept is 4: b = 4

y = (3/4)x + 4

4. The x intercept -3 and the y-intercept is 6

The x-intercept can be written as (-3,0) and the y-intercept as (0,6).

Calculate the slope between these two points (Rise/Run).  Rise= (6-0), or 6,  Run= (0-(-3)), or 3.  Rise/Run (Slope) = 6/3 or 2

y = 2x + b   b = 6 (y-intercept is (0,6)

y = 2x + 6

5. Passing through the points (-1, -2) and (5, 3)

y = mx + b

Slope:  Rise = (3-(-2)) = 5, Run = (5-(-1))= 6  Slope = Rise/Run Slope = (5/6)

y = (5/6)x + b

Calculate b:  

y = (5/6)x + b for (-1,-2)

b = y-(5/6)x

b =-2-(5/6)*(-1)

b = -2 + (5/6)

b = (-12/6) + (5/6) = -(7/6)

y = (5/6)x - (7/6)

For each problem, rearrange the solution to the standard form ax + by = c

1.  y=5x+9

-5x + y = 9

2.  y = -1.2x - 0.4

1.2x + y = -0.4

3.  y = (3/4)x + 4

-(3/4)x + y = 5

4.  y = 2x + 6

-2x + y = 6

5.  y = (5/6)x - (7/6)

-(5/6)x + y = -(7/6)

70,000 + 6,000 + 800 + 30

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.